Keep the good work!

French Version ;)
http://moiscript.weebly.com/geacuteomeacutetries-par-bemfarmer.html

Here on the left Points of the Fibo_Fermat are used for the _voronoi by Max Smirnov ! :)



@Bemfarmer
Can you Add the "Z" altitude on the right Fermat Curve above ? (because I am not dexterous with this language! :(

//>>>> Insert z value formula here, with z value changing depending upon
// randomly selected j value. z value could ramp up from 0 to the next seed,
// and then ramp down to 0 to the next seed.
// Pass z value to Polar2Cartesian function.

Hi Pilou,

I'll have a look...

- Brian

How do you start drawing the Fibonacci flower using only a compass and straight edge?

each square has a quarter circle
(and with colors you can see 2 Fibonacci flowers intricated : a colored one and a black one! :)
Magic geometry!

@Michael

During the "triming" circles / squares i had this message ? (beta v4 17 october 2018 )
(i just drawn circles and squares! ;)



http://moiscript.weebly.com/uploads/3/9/3/8/3938813/alert_message.3dm

Ha, good reminder! So i did a MoI doodle too, based on the Fibonacci Spiral. :-)



Regards
Stefan

Beatiful! Very elegant :)

Thank you Marco! :-)

Regards
Stefan

BTW, for people who like to calculate the Golden Ratio for an image size, for rendering, layout etc. ...

There is a nice free OS X Widget available. :-)

http://www.thismanslife.co.uk/projects/phiculator/

Regards
Stefan

do 360 / phi^3 you get the approximation 85 degrees = 1
then times phi you get this very interesting number 137.5 degrees = phi
2phi + 1 = phi^3 or 1/phi^-3

222.508 would be phi^2 and 275 would be 2 phi Radius = 1

try this experiment: get three equal size sphere magnets (I used Neodymium Iron Boron) and mark the center theta for the first two magnets . Arrange the two magnets on either poles of the third magnet without touching each other (the first two magnets) you get the angle from the center of the two magnets that intersects approximately 85 degrees by 137.5 by 137.5 . The arrangement of the three magnets should look like Y

222.508 would be phi^2 and 275 might be 2 phi Radius = 1

do this test: get three equal length sphere magnets (I used Neodymium Iron Boron) and mark the center theta for the first magnets . set up the 2 magnets on either poles of the third magnet without touching every different (the first magnets) you get the angle from the center of the two magnets that intersects about 85 stages by 137.five by 137.5 . The association of the three magnets need to appear like Y

Ah , thank you for making my explanations more clear. :)

hello is there a way to draw a 137.5 by 85 degree angle using only a compass and a straight edge?

Hi Bob - I'm sorry I don't understand your question, is that something you're trying to draw in MoI ?

- Michael

Yes, I'm trying to construct a Golden angle of 137.5 by 137.5 by 85 degrees approximate in a circle using a compass and a straight edge.Which can be done on a piece of paper.

I recall from math class that the square root of 5 can be so constructed...
- Brian

According to this link, the answer is YES :-)
https://www.johndcook.com/blog/2017/05/01/golden-angle/

But the method is not given...

- Brian

After reading google links on "Constructible Angles," I'll conclude that construction of 137.5 degrees is NOT possible with compass and straigtedge...