Hilbert Curve, Koch Snowflake
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 From:  bemfarmer
6441.18 In reply to 6441.17 
Thank you Thomas.
Your Loft is amazing. Looks like an exotic wood burl, statue, Rorschach, etc.
Does your Loft involve any other processing?

- Brian
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 From:  Tommy (THOMASHELZLE)
6441.19 In reply to 6441.18 
;-)

No, it's pretty much a loft from Levels 1 > 2 > 3 > 4 > 5 > 4 > 3 > 2 > 1 with G3 filleted corners to get the round, organic shape.
It took more than an hour for MoI to build the loft and I can only save it if I set the display meshing to 180°, so that enough memory is remaining to save the mesh as obj for Thea Render.

I think we reached the limits for 32 Bit Software :-)

Cheers,

Tom
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 From:  bemfarmer
6441.20 
Note, the coordinates for the Koch snowflake01 script, are not the corners of an equilateral triangle, so it is not symmetric.
(If the triangle is pointed up, a different pattern occurs.).

Using coordinates of a 3 sided MoI polygon, mirrored to point down, will yield a symmetric snowflake.
For example, (7.5, 2.0096189...) (0, 15) (15,15), where 2.0096189 is 15 minus sqrt(3)*15 / 2.
- Brian


EDITED: 25 Mar 2014 by BEMFARMER


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 From:  bemfarmer
6441.21 
Updated _HilbertCurve3D to work with MoI4betaNov28_2017, by changing comma to semicolon.
- Brian
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