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 From:  Barry-H
10159.1 
Hi,
This is probably very basic but having a brain freeze,
The attached nod file puts circles on a polygon.
I want the circles to be flat not standing up.
Cheers
Barry
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 From:  Frenchy Pilou (PILOU)
10159.2 In reply to 10159.1 
Make a Rotate after the circle ? ;)

Or maybe better Select a Flat circle as object!
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 From:  bemfarmer
10159.3 In reply to 10159.1 
Hi Barry,
Pointarrays have a frame incorporated in their structure.
Posts by Karsten talk about the frames.
Cannot say that I understand them much.
Anyway, Karsten wrote two scripts, splitPts and PointExt which can
be used to change the frame.
Run the output of mPath-Array to pts input of splitPts.
By trial and error:
Outputs of splitPts connect to PointExt as follows:
x-x
y-y
z-z
Rx---no connection
Ry-AngleZ
Rz-AngleX
also connect Rz-AngleY
Point outputs of PointExt node goes to Center of Circle node.
Circle node Out goes to Output.

- Brian

Maybe try Pilou's rotate on the circle instead?

Is there a node to rotate a frame directly?
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 From:  Barry-H
10159.4 In reply to 10159.3 
Hi Brian,
your method worked thanks.
I had tried rotating the circle as Pilou suggested but it does not work.
Thanks again.
Barry
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 From:  Frenchy Pilou (PILOU)
10159.5 
Maybe something like this ?

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 From:  James (JFH)
10159.6 In reply to 10159.1 
Barry,

Brian has already provided you with a universal solution for all point cases.
However when working in 2D on the ground plane, it is not necessary to concern yourself with point rotational data,
hence the Rx, Ry, & Rz outputs need not be connected to ptExt node "angle" inputs, indeed it would suffice to use regular points/point node.
Also Basic/Extract nodes could be used instead of splitPts node, since the only required data outputs are x & y data.
See below


Hope this helps

James
https://www.instagram.com/nodeology/

EDITED: 12 Feb 2021 by JFH

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 From:  Frenchy Pilou (PILOU)
10159.7 
Tricky!
A always find the good Node "color input" to "color Output" is the more difficult when you have not daily practice!
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 From:  Barry-H
10159.8 In reply to 10159.6 
Hi James,
thanks for the explanation.
Barry
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