Brachistochrone Problem
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 From:  bemfarmer
9065.15 In reply to 9065.11 
Hi Yakas,

The existing CycloidInterp script will work, with aRadius = bRadius = 2.5 feet+, mirrored upside down, using half of one cycle.

At a radius of 2.5 feet, the height difference is 5 feet, and the upper tangent is 90 degrees.
At a radius of 3 feet, the height difference is 6 feet, and with one vertical foot removed from the top of the cycloid,
the tangent is about 65.9052 degrees from the horizontal, as measured with Michael's Angle script.

Some more options may be added to the script...

- Brian

(No calculus needed. It has already been proven that without friction, the brachistochrone is a cycloid)
(The CycloidInterp script uses the Trochoid formula. When aRadius = bRadius, the trochoid is a common cycloid)

EDITED: 23 Sep 2018 by BEMFARMER

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 From:  yakas
9065.16 In reply to 9065.15 
Great!

Thanks so much.
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