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From: Frenchy Pilou (PILOU)
French Version ;)
http://moiscript.weebly.com/geacuteomeacutetries-par-bemfarmer.html
Here on the left Points of the Fibo_Fermat are used for the _voronoi by Max Smirnov ! :)
@Bemfarmer
Can you Add the "Z" altitude on the right Fermat Curve above ? (because I am not dexterous with this language! :(
//>>>> Insert z value formula here, with z value changing depending upon
// randomly selected j value. z value could ramp up from 0 to the next seed,
// and then ramp down to 0 to the next seed.
// Pass z value to Polar2Cartesian function.
From: bemfarmer
Hi Pilou,
I'll have a look...
- Brian
From: 864kD1998 (BOB1998)
How do you start drawing the Fibonacci flower using only a compass and straight edge?
From: Frenchy Pilou (PILOU)
each square has a quarter circle
(and with colors you can see 2 Fibonacci flowers intricated : a colored one and a black one! :)
Magic geometry!
From: Frenchy Pilou (PILOU)
@Michael
During the "triming" circles / squares i had this message ? (beta v4 17 october 2018 )
(i just drawn circles and squares! ;)
http://moiscript.weebly.com/uploads/3/9/3/8/3938813/alert_message.3dm
From: amur (STEFAN)
Ha, good reminder! So i did a MoI doodle too, based on the Fibonacci Spiral. :-)
Regards
Stefan
From: mkdm
Beatiful! Very elegant :)
From: amur (STEFAN)
Thank you Marco! :-)
Regards
Stefan
From: amur (STEFAN)
BTW, for people who like to calculate the Golden Ratio for an image size, for rendering, layout etc. ...
There is a nice free OS X Widget available. :-)
http://www.thismanslife.co.uk/projects/phiculator/
Regards
Stefan
From: 864kD1998 (BOB1998)
do 360 / phi^3 you get the approximation 85 degrees = 1
then times phi you get this very interesting number 137.5 degrees = phi
2phi + 1 = phi^3 or 1/phi^-3
222.508 would be phi^2 and 275 would be 2 phi Radius = 1
try this experiment: get three equal size sphere magnets (I used Neodymium Iron Boron) and mark the center theta for the first two magnets . Arrange the two magnets on either poles of the third magnet without touching each other (the first two magnets) you get the angle from the center of the two magnets that intersects approximately 85 degrees by 137.5 by 137.5 . The arrangement of the three magnets should look like Y
From: mimitot
222.508 would be phi^2 and 275 might be 2 phi Radius = 1
do this test: get three equal length sphere magnets (I used Neodymium Iron Boron) and mark the center theta for the first magnets . set up the 2 magnets on either poles of the third magnet without touching every different (the first magnets) you get the angle from the center of the two magnets that intersects about 85 stages by 137.five by 137.5 . The association of the three magnets need to appear like Y
From: 864kD1998 (BOB1998)
Ah , thank you for making my explanations more clear. :)
From: 864kD1998 (BOB1998)
hello is there a way to draw a 137.5 by 85 degree angle using only a compass and a straight edge?
From: Michael Gibson
Hi Bob - I'm sorry I don't understand your question, is that something you're trying to draw in MoI ?
- Michael
From: 864kD1998 (BOB1998)
Yes, I'm trying to construct a Golden angle of 137.5 by 137.5 by 85 degrees approximate in a circle using a compass and a straight edge.Which can be done on a piece of paper.
From: bemfarmer
I recall from math class that the square root of 5 can be so constructed...
- Brian
From: bemfarmer
According to this link, the answer is YES :-)
https://www.johndcook.com/blog/2017/05/01/golden-angle/
But the method is not given...
- Brian
After reading google links on "Constructible Angles," I'll conclude that construction of 137.5 degrees is NOT possible with compass and straigtedge...
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