looking for some advice on creating a triangulated tower

 From:  bemfarmer
8640.2 In reply to 8640.1 
Consider the large central tube to be divided into 3 arcs, 1/3rd the circumference each, and, in a sense, to be equivalent to 3 of the smaller tubes.

A module consists of 2 of the smaller tubes, with the 3rd tube the central 1/3rd.
Each pair of tubes has a zigzag bent metal tube welded between them, for a total of 3 zigzag tubes.
Place 3 modules in a hexagon arrangement, rejoining the center1/3 arc sections, and add 3 more zigzag tubes between adjoining modules.

Instead, one module, with a 4th zigzag tube hanging to one side at the hex angle, can be circular arrayed with 3 copies.

https://www.dxengineering.com/parts/tow-ame25-b3?seid=dxese1&cm_mmc=pla-google-_-shopping-_-dxese1-_-american-tower-company&gclid=CjwKCAjwmqHPBRBQEiwAOvbR84OqvR3y3VfEc4VSQNJk4njGJ1xbLMwu2SO4X3HHlPqw4rz74OxHHxoC8QYQAvD_BwE

Engineering analysis of strength is something else.

- Brian