Thanks, Marco!

That's an "almost" solution. If you draw a square around the circles, you will see that the start and ending distances with the side borders are the complicating parts. This is why I chose the house front as an example.

Like here: If I wanted to have 5 circles evenly spaced out between the horizontal border lines, but with the same distance left and right. Not sure which point to grab as base-point for directional array.




But all in all, this case is rather simple to solve using ordinary mirror and divide operations. I was just wondering if there is a speedier way ...